Proof of Theorem nom22
| Step | Hyp | Ref
| Expression |
| 1 | | oran3 85 |
. . . . . . 7
(a⊥ ∪ b⊥ ) = (a ∩ b)⊥ |
| 2 | 1 | lor 66 |
. . . . . 6
(a ∪ (a⊥ ∪ b⊥ )) = (a ∪ (a ∩
b)⊥ ) |
| 3 | 2 | ax-r1 34 |
. . . . 5
(a ∪ (a ∩ b)⊥ ) = (a ∪ (a⊥ ∪ b⊥ )) |
| 4 | | or12 73 |
. . . . 5
(a ∪ (a⊥ ∪ b⊥ )) = (a⊥ ∪ (a ∪ b⊥ )) |
| 5 | 3, 4 | ax-r2 35 |
. . . 4
(a ∪ (a ∩ b)⊥ ) = (a⊥ ∪ (a ∪ b⊥ )) |
| 6 | | ax-a2 30 |
. . . . 5
((a ∩ b) ∪ (a⊥ ∩ (a ∩ b)⊥ )) = ((a⊥ ∩ (a ∩ b)⊥ ) ∪ (a ∩ b)) |
| 7 | 1 | lan 70 |
. . . . . . . 8
(a⊥ ∩ (a⊥ ∪ b⊥ )) = (a⊥ ∩ (a ∩ b)⊥ ) |
| 8 | 7 | ax-r1 34 |
. . . . . . 7
(a⊥ ∩ (a ∩ b)⊥ ) = (a⊥ ∩ (a⊥ ∪ b⊥ )) |
| 9 | | a5c 113 |
. . . . . . 7
(a⊥ ∩ (a⊥ ∪ b⊥ )) = a⊥ |
| 10 | 8, 9 | ax-r2 35 |
. . . . . 6
(a⊥ ∩ (a ∩ b)⊥ ) = a⊥ |
| 11 | 10 | ax-r5 37 |
. . . . 5
((a⊥ ∩ (a ∩ b)⊥ ) ∪ (a ∩ b)) =
(a⊥ ∪ (a ∩ b)) |
| 12 | 6, 11 | ax-r2 35 |
. . . 4
((a ∩ b) ∪ (a⊥ ∩ (a ∩ b)⊥ )) = (a⊥ ∪ (a ∩ b)) |
| 13 | 5, 12 | 2an 72 |
. . 3
((a ∪ (a ∩ b)⊥ ) ∩ ((a ∩ b) ∪
(a⊥ ∩ (a ∩ b)⊥ ))) = ((a⊥ ∪ (a ∪ b⊥ )) ∩ (a⊥ ∪ (a ∩ b))) |
| 14 | | ancom 68 |
. . 3
((a⊥ ∪ (a ∪ b⊥ )) ∩ (a⊥ ∪ (a ∩ b))) =
((a⊥ ∪ (a ∩ b))
∩ (a⊥ ∪ (a ∪ b⊥ ))) |
| 15 | | lea 152 |
. . . . . 6
(a ∩ b) ≤ a |
| 16 | | leo 150 |
. . . . . 6
a ≤ (a ∪ b⊥ ) |
| 17 | 15, 16 | letr 129 |
. . . . 5
(a ∩ b) ≤ (a ∪
b⊥ ) |
| 18 | 17 | lelor 158 |
. . . 4
(a⊥ ∪ (a ∩ b)) ≤
(a⊥ ∪ (a ∪ b⊥ )) |
| 19 | 18 | df2le2 128 |
. . 3
((a⊥ ∪ (a ∩ b))
∩ (a⊥ ∪ (a ∪ b⊥ ))) = (a⊥ ∪ (a ∩ b)) |
| 20 | 13, 14, 19 | 3tr 62 |
. 2
((a ∪ (a ∩ b)⊥ ) ∩ ((a ∩ b) ∪
(a⊥ ∩ (a ∩ b)⊥ ))) = (a⊥ ∪ (a ∩ b)) |
| 21 | | df-id2 50 |
. 2
(a ≡2 (a ∩ b)) =
((a ∪ (a ∩ b)⊥ ) ∩ ((a ∩ b) ∪
(a⊥ ∩ (a ∩ b)⊥ ))) |
| 22 | | df-i1 43 |
. 2
(a →1 b) = (a⊥ ∪ (a ∩ b)) |
| 23 | 20, 21, 22 | 3tr1 60 |
1
(a ≡2 (a ∩ b)) =
(a →1 b) |