Proof of Theorem oa3to4lem5
| Step | Hyp | Ref
| Expression |
| 1 | | oa3to4lem5.1 |
. 2
((a ∪ b) ∩ (c
∪ d)) ≤ (a ∪ (b ∩
(d ∪ ((a ∪ c) ∩
(b ∪ d))))) |
| 2 | | ax-a2 30 |
. . 3
(b ∪ a) = (a ∪
b) |
| 3 | | ax-a2 30 |
. . 3
(d ∪ c) = (c ∪
d) |
| 4 | 2, 3 | 2an 72 |
. 2
((b ∪ a) ∩ (d
∪ c)) = ((a ∪ b) ∩
(c ∪ d)) |
| 5 | | ancom 68 |
. . . . 5
((b ∪ d) ∩ (a
∪ c)) = ((a ∪ c) ∩
(b ∪ d)) |
| 6 | 5 | lor 66 |
. . . 4
(d ∪ ((b ∪ d) ∩
(a ∪ c))) = (d ∪
((a ∪ c) ∩ (b
∪ d))) |
| 7 | 6 | lan 70 |
. . 3
(b ∩ (d ∪ ((b
∪ d) ∩ (a ∪ c)))) =
(b ∩ (d ∪ ((a
∪ c) ∩ (b ∪ d)))) |
| 8 | 7 | lor 66 |
. 2
(a ∪ (b ∩ (d ∪
((b ∪ d) ∩ (a
∪ c))))) = (a ∪ (b ∩
(d ∪ ((a ∪ c) ∩
(b ∪ d))))) |
| 9 | 1, 4, 8 | le3tr1 132 |
1
((b ∪ a) ∩ (d
∪ c)) ≤ (a ∪ (b ∩
(d ∪ ((b ∪ d) ∩
(a ∪ c))))) |