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Theorem oa4dtoc 949
Description: Derivation of 4-OA law variant.
Hypothesis
Ref Expression
oa4dtoc.1 (b ∩ (((ab) ∪ ((a1 d) ∩ (b1 d))) ∪ (((ac) ∪ ((a1 d) ∩ (c1 d))) ∩ ((bc) ∪ ((b1 d) ∩ (c1 d)))))) ≤ (a1 d)
Assertion
Ref Expression
oa4dtoc (a ∩ (a ∪ (b ∩ (((ab) ∪ ((a1 d) ∩ (b1 d))) ∪ (((ac) ∪ ((a1 d) ∩ (c1 d))) ∩ ((bc) ∪ ((b1 d) ∩ (c1 d)))))))) ≤ d

Proof of Theorem oa4dtoc
StepHypRef Expression
1 oa4dtoc.1 . 2 (b ∩ (((ab) ∪ ((a1 d) ∩ (b1 d))) ∪ (((ac) ∪ ((a1 d) ∩ (c1 d))) ∩ ((bc) ∪ ((b1 d) ∩ (c1 d)))))) ≤ (a1 d)
21oatr 908 1 (a ∩ (a ∪ (b ∩ (((ab) ∪ ((a1 d) ∩ (b1 d))) ∪ (((ac) ∪ ((a1 d) ∩ (c1 d))) ∩ ((bc) ∪ ((b1 d) ∩ (c1 d)))))))) ≤ d
Colors of variables: term
Syntax hints:   ≤ wle 2   wn 4   ∪ wo 6   ∩ wa 7   →1 wi1 13
This theorem was proved from axioms:  ax-a1 29  ax-a2 30  ax-a3 31  ax-a5 33  ax-r1 34  ax-r2 35  ax-r4 36  ax-r5 37  ax-r3 421
This theorem depends on definitions:  df-b 38  df-a 39  df-t 40  df-f 41  df-i1 43  df-le1 122  df-le2 123
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