Proof of Theorem oat
| Step | Hyp | Ref
| Expression |
| 1 | | leor 151 |
. . 3
b ≤ (a ∪ b) |
| 2 | | oml 427 |
. . . . 5
(a ∪ (a⊥ ∩ (a ∪ b))) =
(a ∪ b) |
| 3 | 2 | ax-r1 34 |
. . . 4
(a ∪ b) = (a ∪
(a⊥ ∩ (a ∪ b))) |
| 4 | | lea 152 |
. . . . . 6
(a⊥ ∩ (a ∪ b)) ≤
a⊥ |
| 5 | | oat.1 |
. . . . . 6
(a⊥ ∩ (a ∪ b)) ≤
c |
| 6 | 4, 5 | ler2an 165 |
. . . . 5
(a⊥ ∩ (a ∪ b)) ≤
(a⊥ ∩ c) |
| 7 | 6 | lelor 158 |
. . . 4
(a ∪ (a⊥ ∩ (a ∪ b)))
≤ (a ∪ (a⊥ ∩ c)) |
| 8 | 3, 7 | bltr 130 |
. . 3
(a ∪ b) ≤ (a ∪
(a⊥ ∩ c)) |
| 9 | 1, 8 | letr 129 |
. 2
b ≤ (a ∪ (a⊥ ∩ c)) |
| 10 | | ax-a1 29 |
. . . 4
a = a⊥ ⊥ |
| 11 | 10 | ax-r5 37 |
. . 3
(a ∪ (a⊥ ∩ c)) = (a⊥ ⊥ ∪
(a⊥ ∩ c)) |
| 12 | | df-i1 43 |
. . . 4
(a⊥ →1
c) = (a⊥ ⊥ ∪
(a⊥ ∩ c)) |
| 13 | 12 | ax-r1 34 |
. . 3
(a⊥ ⊥
∪ (a⊥ ∩ c)) = (a⊥ →1 c) |
| 14 | 11, 13 | ax-r2 35 |
. 2
(a ∪ (a⊥ ∩ c)) = (a⊥ →1 c) |
| 15 | 9, 14 | lbtr 131 |
1
b ≤ (a⊥ →1 c) |