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Related theorems GIF version |
| Description: Used to prove →1 "add antecedent" rule in →3 system. |
| Ref | Expression |
|---|---|
| u3lem14aa | (a →3 (a →3 ((b →3 a⊥ ) →3 b⊥ ))) = 1 |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | u3lem14a 773 | . . 3 (a →3 ((b →3 a⊥ ) →3 b⊥ )) = (a →3 (b →3 a)) | |
| 2 | 1 | ud3lem0a 252 | . 2 (a →3 (a →3 ((b →3 a⊥ ) →3 b⊥ ))) = (a →3 (a →3 (b →3 a))) |
| 3 | i3th1 525 | . 2 (a →3 (a →3 (b →3 a))) = 1 | |
| 4 | 2, 3 | ax-r2 35 | 1 (a →3 (a →3 ((b →3 a⊥ ) →3 b⊥ ))) = 1 |
| Colors of variables: term |
| Syntax hints: = wb 1 ⊥ wn 4 1wt 9 →3 wi3 15 |
| This theorem is referenced by: u3lem14aa2 775 |
| This theorem was proved from axioms: ax-a1 29 ax-a2 30 ax-a3 31 ax-a4 32 ax-a5 33 ax-r1 34 ax-r2 35 ax-r4 36 ax-r5 37 ax-r3 421 |
| This theorem depends on definitions: df-b 38 df-a 39 df-t 40 df-f 41 df-i1 43 df-i3 45 df-le1 122 df-le2 123 df-c1 124 df-c2 125 |