Proof of Theorem u3lem2
| Step | Hyp | Ref
| Expression |
| 1 | | comi31 490 |
. . . . 5
a C (a →3 b) |
| 2 | | comid 179 |
. . . . 5
a C a |
| 3 | 1, 2 | u3lemc2 670 |
. . . 4
a C ((a →3 b) →3 a) |
| 4 | 3 | comcom 435 |
. . 3
((a →3 b) →3 a) C a |
| 5 | 4 | u3lemc4 685 |
. 2
(((a →3 b) →3 a) →3 a) = (((a
→3 b) →3
a)⊥ ∪ a) |
| 6 | | u3lem1n 723 |
. . . 4
((a →3 b) →3 a)⊥ = ((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ )) |
| 7 | 6 | ax-r5 37 |
. . 3
(((a →3 b) →3 a)⊥ ∪ a) = (((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ )) ∪ a) |
| 8 | | ax-a2 30 |
. . 3
(((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ )) ∪ a) = (a ∪
((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))) |
| 9 | 7, 8 | ax-r2 35 |
. 2
(((a →3 b) →3 a)⊥ ∪ a) = (a ∪
((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))) |
| 10 | 5, 9 | ax-r2 35 |
1
(((a →3 b) →3 a) →3 a) = (a ∪
((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))) |