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Theorem u4lem2 729
Description: Lemma for unified implication study.
Assertion
Ref Expression
u4lem2 (((a4 b) →4 a) →4 a) = (a ∪ ((ab) ∪ (ab )))

Proof of Theorem u4lem2
StepHypRef Expression
1 u4lemc1 665 . . . 4 a C ((a4 b) →4 a)
21comcom 435 . . 3 ((a4 b) →4 a) C a
32u4lemc4 686 . 2 (((a4 b) →4 a) →4 a) = (((a4 b) →4 a)a)
4 u4lem1n 724 . . . 4 ((a4 b) →4 a) = ((((ab) ∩ (ab )) ∩ a) ∪ ((ab) ∪ (ab )))
54ax-r5 37 . . 3 (((a4 b) →4 a)a) = (((((ab) ∩ (ab )) ∩ a) ∪ ((ab) ∪ (ab ))) ∪ a)
6 ax-a3 31 . . . 4 (((((ab) ∩ (ab )) ∩ a) ∪ ((ab) ∪ (ab ))) ∪ a) = ((((ab) ∩ (ab )) ∩ a) ∪ (((ab) ∪ (ab )) ∪ a))
7 lear 153 . . . . . . 7 (((ab) ∩ (ab )) ∩ a) ≤ a
8 leor 151 . . . . . . 7 a ≤ (((ab) ∪ (ab )) ∪ a)
97, 8letr 129 . . . . . 6 (((ab) ∩ (ab )) ∩ a) ≤ (((ab) ∪ (ab )) ∪ a)
109df-le2 123 . . . . 5 ((((ab) ∩ (ab )) ∩ a) ∪ (((ab) ∪ (ab )) ∪ a)) = (((ab) ∪ (ab )) ∪ a)
11 ax-a2 30 . . . . 5 (((ab) ∪ (ab )) ∪ a) = (a ∪ ((ab) ∪ (ab )))
1210, 11ax-r2 35 . . . 4 ((((ab) ∩ (ab )) ∩ a) ∪ (((ab) ∪ (ab )) ∪ a)) = (a ∪ ((ab) ∪ (ab )))
136, 12ax-r2 35 . . 3 (((((ab) ∩ (ab )) ∩ a) ∪ ((ab) ∪ (ab ))) ∪ a) = (a ∪ ((ab) ∪ (ab )))
145, 13ax-r2 35 . 2 (((a4 b) →4 a)a) = (a ∪ ((ab) ∪ (ab )))
153, 14ax-r2 35 1 (((a4 b) →4 a) →4 a) = (a ∪ ((ab) ∪ (ab )))
Colors of variables: term
Syntax hints:   = wb 1   wn 4   ∪ wo 6   ∩ wa 7   →4 wi4 16
This theorem was proved from axioms:  ax-a1 29  ax-a2 30  ax-a3 31  ax-a4 32  ax-a5 33  ax-r1 34  ax-r2 35  ax-r4 36  ax-r5 37  ax-r3 421
This theorem depends on definitions:  df-b 38  df-a 39  df-t 40  df-f 41  df-i4 46  df-le1 122  df-le2 123  df-c1 124  df-c2 125
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