Proof of Theorem u4lem2
| Step | Hyp | Ref
| Expression |
| 1 | | u4lemc1 665 |
. . . 4
a C ((a →4 b) →4 a) |
| 2 | 1 | comcom 435 |
. . 3
((a →4 b) →4 a) C a |
| 3 | 2 | u4lemc4 686 |
. 2
(((a →4 b) →4 a) →4 a) = (((a
→4 b) →4
a)⊥ ∪ a) |
| 4 | | u4lem1n 724 |
. . . 4
((a →4 b) →4 a)⊥ = ((((a⊥ ∪ b) ∩ (a⊥ ∪ b⊥ )) ∩ a) ∪ ((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))) |
| 5 | 4 | ax-r5 37 |
. . 3
(((a →4 b) →4 a)⊥ ∪ a) = (((((a⊥ ∪ b) ∩ (a⊥ ∪ b⊥ )) ∩ a) ∪ ((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))) ∪ a) |
| 6 | | ax-a3 31 |
. . . 4
(((((a⊥ ∪ b) ∩ (a⊥ ∪ b⊥ )) ∩ a) ∪ ((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))) ∪ a) = ((((a⊥ ∪ b) ∩ (a⊥ ∪ b⊥ )) ∩ a) ∪ (((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ )) ∪ a)) |
| 7 | | lear 153 |
. . . . . . 7
(((a⊥ ∪ b) ∩ (a⊥ ∪ b⊥ )) ∩ a) ≤ a |
| 8 | | leor 151 |
. . . . . . 7
a ≤ (((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ )) ∪ a) |
| 9 | 7, 8 | letr 129 |
. . . . . 6
(((a⊥ ∪ b) ∩ (a⊥ ∪ b⊥ )) ∩ a) ≤ (((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ )) ∪ a) |
| 10 | 9 | df-le2 123 |
. . . . 5
((((a⊥ ∪ b) ∩ (a⊥ ∪ b⊥ )) ∩ a) ∪ (((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ )) ∪ a)) = (((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ )) ∪ a) |
| 11 | | ax-a2 30 |
. . . . 5
(((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ )) ∪ a) = (a ∪
((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))) |
| 12 | 10, 11 | ax-r2 35 |
. . . 4
((((a⊥ ∪ b) ∩ (a⊥ ∪ b⊥ )) ∩ a) ∪ (((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ )) ∪ a)) = (a ∪
((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))) |
| 13 | 6, 12 | ax-r2 35 |
. . 3
(((((a⊥ ∪ b) ∩ (a⊥ ∪ b⊥ )) ∩ a) ∪ ((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))) ∪ a) = (a ∪
((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))) |
| 14 | 5, 13 | ax-r2 35 |
. 2
(((a →4 b) →4 a)⊥ ∪ a) = (a ∪
((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))) |
| 15 | 3, 14 | ax-r2 35 |
1
(((a →4 b) →4 a) →4 a) = (a ∪
((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))) |