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Theorem u4lemab 595
Description: Lemma for non-tollens implication study.
Assertion
Ref Expression
u4lemab ((a4 b) ∩ b) = ((ab) ∪ (ab))

Proof of Theorem u4lemab
StepHypRef Expression
1 df-i4 46 . . 3 (a4 b) = (((ab) ∪ (ab)) ∪ ((ab) ∩ b ))
21ran 71 . 2 ((a4 b) ∩ b) = ((((ab) ∪ (ab)) ∪ ((ab) ∩ b )) ∩ b)
3 comanr2 447 . . . . 5 b C (ab)
4 comanr2 447 . . . . 5 b C (ab)
53, 4com2or 465 . . . 4 b C ((ab) ∪ (ab))
6 comanr2 447 . . . . 5 b C ((ab) ∩ b )
76comcom6 441 . . . 4 b C ((ab) ∩ b )
85, 7fh1r 455 . . 3 ((((ab) ∪ (ab)) ∪ ((ab) ∩ b )) ∩ b) = ((((ab) ∪ (ab)) ∩ b) ∪ (((ab) ∩ b ) ∩ b))
9 lear 153 . . . . . . 7 (ab) ≤ b
10 lear 153 . . . . . . 7 (ab) ≤ b
119, 10lel2or 162 . . . . . 6 ((ab) ∪ (ab)) ≤ b
1211df2le2 128 . . . . 5 (((ab) ∪ (ab)) ∩ b) = ((ab) ∪ (ab))
13 an32 76 . . . . . 6 (((ab) ∩ b ) ∩ b) = (((ab) ∩ b) ∩ b )
14 anass 69 . . . . . . 7 (((ab) ∩ b) ∩ b ) = ((ab) ∩ (bb ))
15 dff 93 . . . . . . . . . 10 0 = (bb )
1615lan 70 . . . . . . . . 9 ((ab) ∩ 0) = ((ab) ∩ (bb ))
1716ax-r1 34 . . . . . . . 8 ((ab) ∩ (bb )) = ((ab) ∩ 0)
18 an0 100 . . . . . . . 8 ((ab) ∩ 0) = 0
1917, 18ax-r2 35 . . . . . . 7 ((ab) ∩ (bb )) = 0
2014, 19ax-r2 35 . . . . . 6 (((ab) ∩ b) ∩ b ) = 0
2113, 20ax-r2 35 . . . . 5 (((ab) ∩ b ) ∩ b) = 0
2212, 212or 67 . . . 4 ((((ab) ∪ (ab)) ∩ b) ∪ (((ab) ∩ b ) ∩ b)) = (((ab) ∪ (ab)) ∪ 0)
23 or0 94 . . . 4 (((ab) ∪ (ab)) ∪ 0) = ((ab) ∪ (ab))
2422, 23ax-r2 35 . . 3 ((((ab) ∪ (ab)) ∩ b) ∪ (((ab) ∩ b ) ∩ b)) = ((ab) ∪ (ab))
258, 24ax-r2 35 . 2 ((((ab) ∪ (ab)) ∪ ((ab) ∩ b )) ∩ b) = ((ab) ∪ (ab))
262, 25ax-r2 35 1 ((a4 b) ∩ b) = ((ab) ∪ (ab))
Colors of variables: term
Syntax hints:   = wb 1   wn 4   ∪ wo 6   ∩ wa 7  0wf 10   →4 wi4 16
This theorem is referenced by:  u4lemnonb 660  u24lem 752
This theorem was proved from axioms:  ax-a1 29  ax-a2 30  ax-a3 31  ax-a4 32  ax-a5 33  ax-r1 34  ax-r2 35  ax-r4 36  ax-r5 37  ax-r3 421
This theorem depends on definitions:  df-b 38  df-a 39  df-t 40  df-f 41  df-i4 46  df-le1 122  df-le2 123  df-c1 124  df-c2 125
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