Proof of Theorem u5lem2
| Step | Hyp | Ref
| Expression |
| 1 | | u5lemc1b 667 |
. . . 4
a C ((a →5 b) →5 a) |
| 2 | 1 | comcom 435 |
. . 3
((a →5 b) →5 a) C a |
| 3 | 2 | u5lemc4 687 |
. 2
(((a →5 b) →5 a) →5 a) = (((a
→5 b) →5
a)⊥ ∪ a) |
| 4 | | u5lem1n 725 |
. . . 4
((a →5 b) →5 a)⊥ = ((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ )) |
| 5 | 4 | ax-r5 37 |
. . 3
(((a →5 b) →5 a)⊥ ∪ a) = (((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ )) ∪ a) |
| 6 | | ax-a2 30 |
. . 3
(((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ )) ∪ a) = (a ∪
((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))) |
| 7 | 5, 6 | ax-r2 35 |
. 2
(((a →5 b) →5 a)⊥ ∪ a) = (a ∪
((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))) |
| 8 | 3, 7 | ax-r2 35 |
1
(((a →5 b) →5 a) →5 a) = (a ∪
((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))) |