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Theorem u5lemaa 586
Description: Lemma for relevance implication study.
Assertion
Ref Expression
u5lemaa ((a5 b) ∩ a) = (ab)

Proof of Theorem u5lemaa
StepHypRef Expression
1 df-i5 47 . . 3 (a5 b) = (((ab) ∪ (ab)) ∪ (ab ))
21ran 71 . 2 ((a5 b) ∩ a) = ((((ab) ∪ (ab)) ∪ (ab )) ∩ a)
3 comanr1 446 . . . . 5 a C (ab)
4 comanr1 446 . . . . . 6 a C (ab)
54comcom6 441 . . . . 5 a C (ab)
63, 5com2or 465 . . . 4 a C ((ab) ∪ (ab))
7 comanr1 446 . . . . 5 a C (ab )
87comcom6 441 . . . 4 a C (ab )
96, 8fh1r 455 . . 3 ((((ab) ∪ (ab)) ∪ (ab )) ∩ a) = ((((ab) ∪ (ab)) ∩ a) ∪ ((ab ) ∩ a))
103, 5fh1r 455 . . . . . 6 (((ab) ∪ (ab)) ∩ a) = (((ab) ∩ a) ∪ ((ab) ∩ a))
11 an32 76 . . . . . . . . 9 ((ab) ∩ a) = ((aa) ∩ b)
12 anidm 103 . . . . . . . . . 10 (aa) = a
1312ran 71 . . . . . . . . 9 ((aa) ∩ b) = (ab)
1411, 13ax-r2 35 . . . . . . . 8 ((ab) ∩ a) = (ab)
15 an32 76 . . . . . . . . 9 ((ab) ∩ a) = ((aa) ∩ b)
16 ancom 68 . . . . . . . . . 10 ((aa) ∩ b) = (b ∩ (aa))
17 ancom 68 . . . . . . . . . . . . . 14 (aa ) = (aa)
1817ax-r1 34 . . . . . . . . . . . . 13 (aa) = (aa )
19 dff 93 . . . . . . . . . . . . . 14 0 = (aa )
2019ax-r1 34 . . . . . . . . . . . . 13 (aa ) = 0
2118, 20ax-r2 35 . . . . . . . . . . . 12 (aa) = 0
2221lan 70 . . . . . . . . . . 11 (b ∩ (aa)) = (b ∩ 0)
23 an0 100 . . . . . . . . . . 11 (b ∩ 0) = 0
2422, 23ax-r2 35 . . . . . . . . . 10 (b ∩ (aa)) = 0
2516, 24ax-r2 35 . . . . . . . . 9 ((aa) ∩ b) = 0
2615, 25ax-r2 35 . . . . . . . 8 ((ab) ∩ a) = 0
2714, 262or 67 . . . . . . 7 (((ab) ∩ a) ∪ ((ab) ∩ a)) = ((ab) ∪ 0)
28 or0 94 . . . . . . 7 ((ab) ∪ 0) = (ab)
2927, 28ax-r2 35 . . . . . 6 (((ab) ∩ a) ∪ ((ab) ∩ a)) = (ab)
3010, 29ax-r2 35 . . . . 5 (((ab) ∪ (ab)) ∩ a) = (ab)
31 ancom 68 . . . . 5 ((ab ) ∩ a) = (a ∩ (ab ))
3230, 312or 67 . . . 4 ((((ab) ∪ (ab)) ∩ a) ∪ ((ab ) ∩ a)) = ((ab) ∪ (a ∩ (ab )))
333, 8fh4 454 . . . . 5 ((ab) ∪ (a ∩ (ab ))) = (((ab) ∪ a) ∩ ((ab) ∪ (ab )))
34 ax-a2 30 . . . . . . . 8 ((ab) ∪ a) = (a ∪ (ab))
35 a5b 112 . . . . . . . 8 (a ∪ (ab)) = a
3634, 35ax-r2 35 . . . . . . 7 ((ab) ∪ a) = a
3736ran 71 . . . . . 6 (((ab) ∪ a) ∩ ((ab) ∪ (ab ))) = (a ∩ ((ab) ∪ (ab )))
383, 8fh1 451 . . . . . . 7 (a ∩ ((ab) ∪ (ab ))) = ((a ∩ (ab)) ∪ (a ∩ (ab )))
39 anass 69 . . . . . . . . . . 11 ((aa) ∩ b) = (a ∩ (ab))
4039ax-r1 34 . . . . . . . . . 10 (a ∩ (ab)) = ((aa) ∩ b)
4140, 13ax-r2 35 . . . . . . . . 9 (a ∩ (ab)) = (ab)
42 anass 69 . . . . . . . . . . 11 ((aa ) ∩ b ) = (a ∩ (ab ))
4342ax-r1 34 . . . . . . . . . 10 (a ∩ (ab )) = ((aa ) ∩ b )
44 ancom 68 . . . . . . . . . . 11 ((aa ) ∩ b ) = (b ∩ (aa ))
4519lan 70 . . . . . . . . . . . . 13 (b ∩ 0) = (b ∩ (aa ))
4645ax-r1 34 . . . . . . . . . . . 12 (b ∩ (aa )) = (b ∩ 0)
47 an0 100 . . . . . . . . . . . 12 (b ∩ 0) = 0
4846, 47ax-r2 35 . . . . . . . . . . 11 (b ∩ (aa )) = 0
4944, 48ax-r2 35 . . . . . . . . . 10 ((aa ) ∩ b ) = 0
5043, 49ax-r2 35 . . . . . . . . 9 (a ∩ (ab )) = 0
5141, 502or 67 . . . . . . . 8 ((a ∩ (ab)) ∪ (a ∩ (ab ))) = ((ab) ∪ 0)
5251, 28ax-r2 35 . . . . . . 7 ((a ∩ (ab)) ∪ (a ∩ (ab ))) = (ab)
5338, 52ax-r2 35 . . . . . 6 (a ∩ ((ab) ∪ (ab ))) = (ab)
5437, 53ax-r2 35 . . . . 5 (((ab) ∪ a) ∩ ((ab) ∪ (ab ))) = (ab)
5533, 54ax-r2 35 . . . 4 ((ab) ∪ (a ∩ (ab ))) = (ab)
5632, 55ax-r2 35 . . 3 ((((ab) ∪ (ab)) ∩ a) ∪ ((ab ) ∩ a)) = (ab)
579, 56ax-r2 35 . 2 ((((ab) ∪ (ab)) ∪ (ab )) ∩ a) = (ab)
582, 57ax-r2 35 1 ((a5 b) ∩ a) = (ab)
Colors of variables: term
Syntax hints:   = wb 1   wn 4   ∪ wo 6   ∩ wa 7  0wf 10   →5 wi5 17
This theorem is referenced by:  u5lemnona 651  u5lembi 707
This theorem was proved from axioms:  ax-a1 29  ax-a2 30  ax-a3 31  ax-a4 32  ax-a5 33  ax-r1 34  ax-r2 35  ax-r4 36  ax-r5 37  ax-r3 421
This theorem depends on definitions:  df-b 38  df-a 39  df-t 40  df-f 41  df-i5 47  df-le1 122  df-le2 123  df-c1 124  df-c2 125
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