Theorem u5lemana 591

Description: Lemma for relevance implication study.

Assertion

Ref	Expression
u5lemana	((a →5 b) ∩ a⊥ ) = ((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))

Proof of Theorem u5lemana

Step	Hyp	Ref	Expression
1		df-i5 47	. . 3 (a →5 b) = (((a ∩ b) ∪ (a⊥ ∩ b)) ∪ (a⊥ ∩ b⊥ ))
2	1	ran 71	. 2 ((a →5 b) ∩ a⊥ ) = ((((a ∩ b) ∪ (a⊥ ∩ b)) ∪ (a⊥ ∩ b⊥ )) ∩ a⊥ )
3		comanr1 446	. . . . . 6 a C (a ∩ b)
4	3	comcom3 436	. . . . 5 a⊥ C (a ∩ b)
5		comanr1 446	. . . . 5 a⊥ C (a⊥ ∩ b)
6	4, 5	com2or 465	. . . 4 a⊥ C ((a ∩ b) ∪ (a⊥ ∩ b))
7		comanr1 446	. . . 4 a⊥ C (a⊥ ∩ b⊥ )
8	6, 7	fh1r 455	. . 3 ((((a ∩ b) ∪ (a⊥ ∩ b)) ∪ (a⊥ ∩ b⊥ )) ∩ a⊥ ) = ((((a ∩ b) ∪ (a⊥ ∩ b)) ∩ a⊥ ) ∪ ((a⊥ ∩ b⊥ ) ∩ a⊥ ))
9	4, 5	fh1r 455	. . . . 5 (((a ∩ b) ∪ (a⊥ ∩ b)) ∩ a⊥ ) = (((a ∩ b) ∩ a⊥ ) ∪ ((a⊥ ∩ b) ∩ a⊥ ))
10		ax-a2 30	. . . . . 6 (((a ∩ b) ∩ a⊥ ) ∪ ((a⊥ ∩ b) ∩ a⊥ )) = (((a⊥ ∩ b) ∩ a⊥ ) ∪ ((a ∩ b) ∩ a⊥ ))
11		an32 76	. . . . . . . . 9 ((a⊥ ∩ b) ∩ a⊥ ) = ((a⊥ ∩ a⊥ ) ∩ b)
12		anidm 103	. . . . . . . . . 10 (a⊥ ∩ a⊥ ) = a⊥
13	12	ran 71	. . . . . . . . 9 ((a⊥ ∩ a⊥ ) ∩ b) = (a⊥ ∩ b)
14	11, 13	ax-r2 35	. . . . . . . 8 ((a⊥ ∩ b) ∩ a⊥ ) = (a⊥ ∩ b)
15		an32 76	. . . . . . . . 9 ((a ∩ b) ∩ a⊥ ) = ((a ∩ a⊥ ) ∩ b)
16		ancom 68	. . . . . . . . . 10 ((a ∩ a⊥ ) ∩ b) = (b ∩ (a ∩ a⊥ ))
17		dff 93	. . . . . . . . . . . . 13 0 = (a ∩ a⊥ )
18	17	lan 70	. . . . . . . . . . . 12 (b ∩ 0) = (b ∩ (a ∩ a⊥ ))
19	18	ax-r1 34	. . . . . . . . . . 11 (b ∩ (a ∩ a⊥ )) = (b ∩ 0)
20		an0 100	. . . . . . . . . . 11 (b ∩ 0) = 0
21	19, 20	ax-r2 35	. . . . . . . . . 10 (b ∩ (a ∩ a⊥ )) = 0
22	16, 21	ax-r2 35	. . . . . . . . 9 ((a ∩ a⊥ ) ∩ b) = 0
23	15, 22	ax-r2 35	. . . . . . . 8 ((a ∩ b) ∩ a⊥ ) = 0
24	14, 23	2or 67	. . . . . . 7 (((a⊥ ∩ b) ∩ a⊥ ) ∪ ((a ∩ b) ∩ a⊥ )) = ((a⊥ ∩ b) ∪ 0)
25		or0 94	. . . . . . 7 ((a⊥ ∩ b) ∪ 0) = (a⊥ ∩ b)
26	24, 25	ax-r2 35	. . . . . 6 (((a⊥ ∩ b) ∩ a⊥ ) ∪ ((a ∩ b) ∩ a⊥ )) = (a⊥ ∩ b)
27	10, 26	ax-r2 35	. . . . 5 (((a ∩ b) ∩ a⊥ ) ∪ ((a⊥ ∩ b) ∩ a⊥ )) = (a⊥ ∩ b)
28	9, 27	ax-r2 35	. . . 4 (((a ∩ b) ∪ (a⊥ ∩ b)) ∩ a⊥ ) = (a⊥ ∩ b)
29		an32 76	. . . . 5 ((a⊥ ∩ b⊥ ) ∩ a⊥ ) = ((a⊥ ∩ a⊥ ) ∩ b⊥ )
30	12	ran 71	. . . . 5 ((a⊥ ∩ a⊥ ) ∩ b⊥ ) = (a⊥ ∩ b⊥ )
31	29, 30	ax-r2 35	. . . 4 ((a⊥ ∩ b⊥ ) ∩ a⊥ ) = (a⊥ ∩ b⊥ )
32	28, 31	2or 67	. . 3 ((((a ∩ b) ∪ (a⊥ ∩ b)) ∩ a⊥ ) ∪ ((a⊥ ∩ b⊥ ) ∩ a⊥ )) = ((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))
33	8, 32	ax-r2 35	. 2 ((((a ∩ b) ∪ (a⊥ ∩ b)) ∪ (a⊥ ∩ b⊥ )) ∩ a⊥ ) = ((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))
34	2, 33	ax-r2 35	1 ((a →5 b) ∩ a⊥ ) = ((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))

Syntax hints:   = wb 1  ^⊥ wn 4   ∪ wo 6   ∩ wa 7  0wf 10   →₅ wi5 17

This theorem is referenced by:  u5lemnoa 646

This theorem was proved from axioms:  ax-a1 29  ax-a2 30  ax-a3 31  ax-a4 32  ax-a5 33  ax-r1 34  ax-r2 35  ax-r4 36  ax-r5 37  ax-r3 421

This theorem depends on definitions:  df-b 38  df-a 39  df-t 40  df-f 41  df-i5 47  df-le1 122  df-le2 123  df-c1 124  df-c2 125

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