Theorem u5lemnana 631

Description: Lemma for relevance implication study.

Assertion

Ref	Expression
u5lemnana	((a →5 b)⊥ ∩ a⊥ ) = (a⊥ ∩ ((a ∪ b) ∩ (a ∪ b⊥ )))

Proof of Theorem u5lemnana

Step	Hyp	Ref	Expression
1		u5lemoa 606	. . . 4 ((a →5 b) ∪ a) = (a ∪ ((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ )))
2		ax-a2 30	. . . . . 6 ((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ )) = ((a⊥ ∩ b⊥ ) ∪ (a⊥ ∩ b))
3		anor3 82	. . . . . . . 8 (a⊥ ∩ b⊥ ) = (a ∪ b)⊥
4		anor2 81	. . . . . . . 8 (a⊥ ∩ b) = (a ∪ b⊥ )⊥
5	3, 4	2or 67	. . . . . . 7 ((a⊥ ∩ b⊥ ) ∪ (a⊥ ∩ b)) = ((a ∪ b)⊥ ∪ (a ∪ b⊥ )⊥ )
6		oran3 85	. . . . . . 7 ((a ∪ b)⊥ ∪ (a ∪ b⊥ )⊥ ) = ((a ∪ b) ∩ (a ∪ b⊥ ))⊥
7	5, 6	ax-r2 35	. . . . . 6 ((a⊥ ∩ b⊥ ) ∪ (a⊥ ∩ b)) = ((a ∪ b) ∩ (a ∪ b⊥ ))⊥
8	2, 7	ax-r2 35	. . . . 5 ((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ )) = ((a ∪ b) ∩ (a ∪ b⊥ ))⊥
9	8	lor 66	. . . 4 (a ∪ ((a⊥ ∩ b) ∪ (a⊥ ∩ b⊥ ))) = (a ∪ ((a ∪ b) ∩ (a ∪ b⊥ ))⊥ )
10	1, 9	ax-r2 35	. . 3 ((a →5 b) ∪ a) = (a ∪ ((a ∪ b) ∩ (a ∪ b⊥ ))⊥ )
11		oran 79	. . 3 ((a →5 b) ∪ a) = ((a →5 b)⊥ ∩ a⊥ )⊥
12		oran1 83	. . 3 (a ∪ ((a ∪ b) ∩ (a ∪ b⊥ ))⊥ ) = (a⊥ ∩ ((a ∪ b) ∩ (a ∪ b⊥ )))⊥
13	10, 11, 12	3tr2 61	. 2 ((a →5 b)⊥ ∩ a⊥ )⊥ = (a⊥ ∩ ((a ∪ b) ∩ (a ∪ b⊥ )))⊥
14	13	con1 63	1 ((a →5 b)⊥ ∩ a⊥ ) = (a⊥ ∩ ((a ∪ b) ∩ (a ∪ b⊥ )))

Syntax hints:   = wb 1  ^⊥ wn 4   ∪ wo 6   ∩ wa 7   →₅ wi5 17

This theorem was proved from axioms:  ax-a1 29  ax-a2 30  ax-a3 31  ax-a5 33  ax-r1 34  ax-r2 35  ax-r4 36  ax-r5 37

This theorem depends on definitions:  df-a 39  df-i5 47

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