Proof of Theorem u5lemonb
| Step | Hyp | Ref
| Expression |
| 1 | | df-i5 47 |
. . 3
(a →5 b) = (((a ∩
b) ∪ (a⊥ ∩ b)) ∪ (a⊥ ∩ b⊥ )) |
| 2 | 1 | ax-r5 37 |
. 2
((a →5 b) ∪ b⊥ ) = ((((a ∩ b) ∪
(a⊥ ∩ b)) ∪ (a⊥ ∩ b⊥ )) ∪ b⊥ ) |
| 3 | | ax-a3 31 |
. . 3
((((a ∩ b) ∪ (a⊥ ∩ b)) ∪ (a⊥ ∩ b⊥ )) ∪ b⊥ ) = (((a ∩ b) ∪
(a⊥ ∩ b)) ∪ ((a⊥ ∩ b⊥ ) ∪ b⊥ )) |
| 4 | | lear 153 |
. . . . 5
(a⊥ ∩ b⊥ ) ≤ b⊥ |
| 5 | 4 | df-le2 123 |
. . . 4
((a⊥ ∩ b⊥ ) ∪ b⊥ ) = b⊥ |
| 6 | 5 | lor 66 |
. . 3
(((a ∩ b) ∪ (a⊥ ∩ b)) ∪ ((a⊥ ∩ b⊥ ) ∪ b⊥ )) = (((a ∩ b) ∪
(a⊥ ∩ b)) ∪ b⊥ ) |
| 7 | 3, 6 | ax-r2 35 |
. 2
((((a ∩ b) ∪ (a⊥ ∩ b)) ∪ (a⊥ ∩ b⊥ )) ∪ b⊥ ) = (((a ∩ b) ∪
(a⊥ ∩ b)) ∪ b⊥ ) |
| 8 | 2, 7 | ax-r2 35 |
1
((a →5 b) ∪ b⊥ ) = (((a ∩ b) ∪
(a⊥ ∩ b)) ∪ b⊥ ) |