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Theorem ud4lem0c 272
Description: Lemma for unified disjunction.
Assertion
Ref Expression
ud4lem0c (a4 b) = (((ab ) ∩ (ab )) ∩ ((ab ) ∪ b))

Proof of Theorem ud4lem0c
StepHypRef Expression
1 df-i4 46 . . 3 (a4 b) = (((ab) ∪ (ab)) ∪ ((ab) ∩ b ))
2 oran 79 . . . 4 (((ab) ∪ (ab)) ∪ ((ab) ∩ b )) = (((ab) ∪ (ab)) ∩ ((ab) ∩ b ) )
3 oran 79 . . . . . . . 8 ((ab) ∪ (ab)) = ((ab) ∩ (ab) )
4 df-a 39 . . . . . . . . . . 11 (ab) = (ab )
54con2 64 . . . . . . . . . 10 (ab) = (ab )
6 anor2 81 . . . . . . . . . . 11 (ab) = (ab )
76con2 64 . . . . . . . . . 10 (ab) = (ab )
85, 72an 72 . . . . . . . . 9 ((ab) ∩ (ab) ) = ((ab ) ∩ (ab ))
98ax-r4 36 . . . . . . . 8 ((ab) ∩ (ab) ) = ((ab ) ∩ (ab ))
103, 9ax-r2 35 . . . . . . 7 ((ab) ∪ (ab)) = ((ab ) ∩ (ab ))
1110con2 64 . . . . . 6 ((ab) ∪ (ab)) = ((ab ) ∩ (ab ))
12 anor1 80 . . . . . . . 8 ((ab) ∩ b ) = ((ab)b)
13 anor1 80 . . . . . . . . . . 11 (ab ) = (ab)
1413ax-r1 34 . . . . . . . . . 10 (ab) = (ab )
1514ax-r5 37 . . . . . . . . 9 ((ab)b) = ((ab ) ∪ b)
1615ax-r4 36 . . . . . . . 8 ((ab)b) = ((ab ) ∪ b)
1712, 16ax-r2 35 . . . . . . 7 ((ab) ∩ b ) = ((ab ) ∪ b)
1817con2 64 . . . . . 6 ((ab) ∩ b ) = ((ab ) ∪ b)
1911, 182an 72 . . . . 5 (((ab) ∪ (ab)) ∩ ((ab) ∩ b ) ) = (((ab ) ∩ (ab )) ∩ ((ab ) ∪ b))
2019ax-r4 36 . . . 4 (((ab) ∪ (ab)) ∩ ((ab) ∩ b ) ) = (((ab ) ∩ (ab )) ∩ ((ab ) ∪ b))
212, 20ax-r2 35 . . 3 (((ab) ∪ (ab)) ∪ ((ab) ∩ b )) = (((ab ) ∩ (ab )) ∩ ((ab ) ∪ b))
221, 21ax-r2 35 . 2 (a4 b) = (((ab ) ∩ (ab )) ∩ ((ab ) ∪ b))
2322con2 64 1 (a4 b) = (((ab ) ∩ (ab )) ∩ ((ab ) ∪ b))
Colors of variables: term
Syntax hints:   = wb 1   wn 4   ∪ wo 6   ∩ wa 7   →4 wi4 16
This theorem is referenced by:  ud4lem1b 560  ud4lem1c 561  ud4lem1d 562  ud4lem3a 565  ud4lem3b 566  u4lem5 746
This theorem was proved from axioms:  ax-a1 29  ax-a2 30  ax-r1 34  ax-r2 35  ax-r4 36  ax-r5 37
This theorem depends on definitions:  df-a 39  df-i4 46
metamath.org