[Lattice L46-7]Home PageHome Quantum Logic Explorer < Previous   Next >
Related theorems
GIF version

Theorem wlem1 235
Description: Lemma for 2-variable WOML proof.
Assertion
Ref Expression
wlem1 ((ab) ∪ ((a1 b) ∩ (b1 a))) = 1

Proof of Theorem wlem1
StepHypRef Expression
1 le1 138 . 2 ((ab) ∪ ((a1 b) ∩ (b1 a))) ≤ 1
2 df-t 40 . . . 4 1 = ((ab) ∪ (ab) )
3 ax-a2 30 . . . 4 ((ab) ∪ (ab) ) = ((ab) ∪ (ab))
42, 3ax-r2 35 . . 3 1 = ((ab) ∪ (ab))
5 dfb 86 . . . . 5 (ab) = ((ab) ∪ (ab ))
6 ledio 168 . . . . . 6 ((ab) ∪ (ab )) ≤ (((ab) ∪ a ) ∩ ((ab) ∪ b ))
7 df-i1 43 . . . . . . . . 9 (a1 b) = (a ∪ (ab))
8 ax-a2 30 . . . . . . . . 9 (a ∪ (ab)) = ((ab) ∪ a )
97, 8ax-r2 35 . . . . . . . 8 (a1 b) = ((ab) ∪ a )
10 df-i1 43 . . . . . . . . 9 (b1 a) = (b ∪ (ba))
11 ax-a2 30 . . . . . . . . . 10 (b ∪ (ba)) = ((ba) ∪ b )
12 ancom 68 . . . . . . . . . . 11 (ba) = (ab)
1312ax-r5 37 . . . . . . . . . 10 ((ba) ∪ b ) = ((ab) ∪ b )
1411, 13ax-r2 35 . . . . . . . . 9 (b ∪ (ba)) = ((ab) ∪ b )
1510, 14ax-r2 35 . . . . . . . 8 (b1 a) = ((ab) ∪ b )
169, 152an 72 . . . . . . 7 ((a1 b) ∩ (b1 a)) = (((ab) ∪ a ) ∩ ((ab) ∪ b ))
1716ax-r1 34 . . . . . 6 (((ab) ∪ a ) ∩ ((ab) ∪ b )) = ((a1 b) ∩ (b1 a))
186, 17lbtr 131 . . . . 5 ((ab) ∪ (ab )) ≤ ((a1 b) ∩ (b1 a))
195, 18bltr 130 . . . 4 (ab) ≤ ((a1 b) ∩ (b1 a))
2019lelor 158 . . 3 ((ab) ∪ (ab)) ≤ ((ab) ∪ ((a1 b) ∩ (b1 a)))
214, 20bltr 130 . 2 1 ≤ ((ab) ∪ ((a1 b) ∩ (b1 a)))
221, 21lebi 137 1 ((ab) ∪ ((a1 b) ∩ (b1 a))) = 1
Colors of variables: term
Syntax hints:   = wb 1   wn 4   ≡ tb 5   ∪ wo 6   ∩ wa 7  1wt 9   →1 wi1 13
This theorem is referenced by:  wr5-2v 348
This theorem was proved from axioms:  ax-a1 29  ax-a2 30  ax-a3 31  ax-a4 32  ax-a5 33  ax-r1 34  ax-r2 35  ax-r4 36  ax-r5 37
This theorem depends on definitions:  df-b 38  df-a 39  df-t 40  df-f 41  df-i1 43  df-le1 122  df-le2 123
metamath.org